I Need Help With Python ...

[rufus777]

import os

#Pidgin-2.7.9 HTTP

os.system("wget http://sourceforge.net/projects/pidgin/files/Pidgin/2.7.9/pidgin-2.7.9.exe")

#Spotify HTTP

os.system("wget http://download.spotify.com/Spotify%20Installer.exe")

#Pidgin-2.7.9 Install

os.system("pidgin-2.7.9.exe")

#Spotify Install

os.system("spotify installer.exe") <------------- 'spotify' is not recognized as an internal or external command,

operable program or batch file.

How should I use "(space)" in os.system???

[Jason Cooper]

Assuming you are using a version of python beyond 2.5 you can, and should, use the subprocess.call instead of the os.system routine.

[rufus777]

Assuming you are using a version of python beyond 2.5 you can, and should, use the subprocess.call instead of the os.system routine.

hehe, thanks!

[sablefoxx]

You shouldn't make system calls if possible (they're evil), it's actually easy to download files in pure python.

Heres a quick example;

import urllib

from subprocess import Popen

path = 'C:\\file.exe'                      # Local path
url = 'http://remote-server.com/file.exe'  # Remote path

connection = urllib.urlopen(url)
remoteFile = connection.read()
connection.close()

try:
    localFile = open(path, 'w')
    localFile.write(remoteFile)
    localFile.close()
    Popen(path) # Execute whatever "path" points to
except IOError:
    print '***** OMFG ERROR: Location is not writable %s *****\n' % path

Using sys.argv you can even make the 'url' a command line argument.

Edited January 27, 2011 by sablefoxx

[P@c_M@n]

You shouldn't make system calls if possible (they're evil), it's actually easy to download files in pure python.

Heres a quick example;

import urllib

from subprocess import Popen

path = 'C:\\file.exe'                      # Local path
url = 'http://remote-server.com/file.exe'  # Remote path

connection = urllib.urlopen(url)
remoteFile = connection.read()
connection.close()

try:
    localFile = open(path, 'w')
    localFile.write(remoteFile)
    localFile.close()
    Popen(path) # Execute whatever "path" points to
except IOError:
    print '***** OMFG ERROR: Location is not writable %s *****\n' % path

Using sys.argv you can even make the 'url' a command line argument.

Just a suggestion, but instead of using all that code with urllib.urlopen() couldn't you just use urllib.urlretrieve() to grab the file instead? I tried your code on a picture and it jumbled up all the pixels. So this is what i came up with

import urllib

path="C:\\file.exe" #local path
url="http://www.example.com/file.exe" #remote path

urllib.urlretrieve(url,path)

It seems a lot simpler just to do this instead.