That's a cool piece of code. I ported it to python as a self imposed exercise (I used 3 loops for my original approach to the problem).
import re; print " ".join([rev_word[::-1] for rev_word in "".join([chr(int(hex_char,16)) for hex_char in re.findall("..", "".join([chr(int(bin_char,2)) for bin_char in re.findall("([01]{8})","00110101001100100011011000110001001101100110001100110
Competition
in Security
Posted
That's a cool piece of code. I ported it to python as a self imposed exercise (I used 3 loops for my original approach to the problem).
import re; print " ".join([rev_word[::-1] for rev_word in "".join([chr(int(hex_char,16)) for hex_char in re.findall("..", "".join([chr(int(bin_char,2)) for bin_char in re.findall("([01]{8})","00110101001100100011011000110001001101100110001100110
110011001100011011100110000001100100011000000110111001100110011
011100110010001101100011000100110110001101010011011000110010001
100100011000000110110001101010011011100110010001101100011000100
110010001100000011011001100010001101100110010100110110001110010
011011100110000001100100110001100110010001100000011011100111001
001101100011010100110110001110000011011100110100001100100011000
000110111001101000011011100110011001101110011010100110110011000
010011001000110000001101110011010000110111001101010011011100110
000001100100011000000110111001101000011011001100110001101100110
001100110110001100010011001000110000001101100011011000110110011
001100011001000110000001101110011000000110111001101010011011000
110101001101100110001000110110001100010011011001100100001100100
0110000001101100110010100110110011001100011001001100101")]))]).split(' ')])
readeable, huh?