Randomly start a file?

[Thermoptic]

Hi! First post here, Great show, great forum!

I just got a remote control for my pc (ATI Remote Wonder 2) And im going to use this to control winamp, video etc.

There are 6 buttons that you can customize on this remote, i have placed a winamp playlist file to start when i press on one of these buttons. But i want to have more that just 6 playlists. So i got this idea.

I'm looking for a program that can start a file randomly from a specific folder.

This way i can just attach this randomizer program to one of the buttons on the remote. And just press it some this to get different playlists from this folder.

It could just be a exe called random.exe that i put in the same dir as the .pls files and when i run this it starts one of the files in this dir.

Or is it possible to do this via a bat script?

Thanks!

[pseudobreed]

Copy and paste the code into a .vbs file in the directory of your playlist.

Dim oFolder

Dim oFile

Dim iCount

Dim Random

ReDim szaFiles(0)



Set wshShell = CreateObject("WScript.Shell")

Set FSO = CreateObject("Scripting.FileSystemObject")

Set oFolder = FSO.GetFolder(".")

For Each oFile In oFolder.Files

  iCount = UBound(szaFiles) + 1

  ReDim Preserve szaFiles(iCount)

  szaFiles(iCount) = oFile.Path

Next



Randomize

Random = Int((iCount) * Rnd + 1)

wshShell.Run chr(34) & szaFiles(Random) & chr(34)

Then just have your remote call the .vbs file.

[Thermoptic]

Thanks pseudobreed! The Code works great.