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user404

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  1. 2-dimensional, 1xn :P Nah, you're right. Din engelsk er ok.
  2. Eh, what can you do... it's from 1998!
  3. yeah, i'm going through an old C book of exercises...
  4. problem 3: find out from how many not falling sequences is the matrix made of e.g. 4 32 5 1 2 6 7 answer 3 solution: #include <stdio.h> int main(void){ int matrix[]={3,3,5,6,3,25,6,3,6,7,8,6}; //answer should be 5 int counter=1; int i; for(i=1; i<sizeof(matrix)/sizeof(matrix[0]); i++){ if(matrix[i-1]>matrix[i]) counter++; } printf(" %d sequences\n", counter); return 0; } ~ ~ ~ ~
  5. On to problem 2: Given n, write a random permutation of numbers from 1 to n. e.g. n=6 3 5 4 1 2 6 my solution: #include <stdio.h> #include <stdlib.h> #include <time.h> #define MAX 50 int main(void){ int n; int rand_matrix[MAX]; int permutation[MAX]; srand(time(NULL)); printf(" n (max %d) = ", MAX); scanf("%d", &n); int i; for(i=0; i<n; i++){ //puts n random numbers in matrix rand_matrix[i]=rand(); } int min_matrix=RAND_MAX; int min_i; int j=0; i=0; do{ if(rand_matrix[i]<=min_matrix){ //have I found a smaller number? min_matrix=rand_matrix[i]; min_i = i; } i++; if(i==n){ //one cycle through the matrix permutation[j++]=min_i+1; rand_matrix[min_i]=RAND_MAX; //prepare for next cycle i=0; min_matrix=RAND_MAX; } }while(j<=n && j<MAX); for(i=0; i<n; i++){ printf(" %d", permutation[i]); } printf("\n"); return 0; }
  6. Hello! I'm learning C, so I'll be posting the problems I'm solving here, join in if you want and post your solutions in your favorite language. Challenge 1: Write a program that reads numbers, until it reads 0, and then outputs them in reverse order. Solution: #include <stdio.h> #define MAX 100 int main(void){ int matrix[MAX]; int num, i=0; printf(" Input at most %d integers, stop with 0\n", MAX); do{ printf(" number[%d] = ", i); scanf("%d", &num); if(num==0) break; matrix[i]=num; i++; } while( i< MAX ); while(i--) printf(" %d", matrix[i]); printf("\n"); return 0; }
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